Converting Signed byte array content to decimal with shifting in java -

i had byte array hex decimal values , converted array decimal values, using following code

byte[] content = message.getfieldvalue( "_decoder message" ).data(); int[] deccontent = new int[ content.length ]; int = 0; ( byte b : content )    deccontent[ i++ ] = b & 0xff; 

now array looks deccontent = [01 00 05 00 00 00] ;

the first 2 indexes of array converted , saved int value below

 int traceidlow = deccontent[ 0 ] & 0xff;  int traceidhigh = deccontent[ 1 ] & 0xff;  int traceid = traceidlow | ( traceidhigh << 8 ); 

the last 4 indexes needs converted int confused shifting whether should 8 or 16 .

how can convert last 4 indexes int value according above example value becomes

00 00 00 05 = 5 in decimal. 

any ideas?

thanks

something this:

int val = deccontent[ 2 ] | (deccontent[ 3 ] << 8)   | (deccontent[ 4 ] << 16) | (deccontent[ 5 ] << 24); 

note integer signed in java. if value unsigned , can larger integer.max_value have put long instead.

a little test:

public static void main(string[] args) throws ioexception {     int[] deccontent = new int[] {1,0,5,0,0,0};     int val = deccontent[ 2 ] | (deccontent[ 3 ] << 8)               | (deccontent[ 4 ] << 16) | (deccontent[ 5 ] << 24);     system.out.println(val); } 

prints answer 5.