scala - How to pass arguments to a function of arbitrary number of parameters via macro? -

i have deconstructed function, got vparams, , able call:

  case class action(f: function, ts: list[typename]) {     def render(rulename: string): expr[unit] = c.expr[unit](q"""       val p = ${c.prefix}       val value1 = p.valuestack.pop().asinstanceof[${ts(0)}]       val value2 = p.valuestack.pop().asinstanceof[${ts(1)}]       p.valuestack.push($f(value1, value2))     """)   } 

f of arbitrary number of parameters known @ compile time.

how pass ts.count parameters p.valuestack function f?

how this:

case class action(f: function, ts: list[typename]) {   def render(rulename: string): expr[unit] = {     val argnames = (1 ts.size).map(i => newtermname(s"value$i"))     val args = argnames.map(name => ident(name))     val valdefs = (ts zip argnames).map {       case (tn, argname) =>         q"val $argname = p.valuestack.pop().asinstanceof[$tn]"     }      c.expr[unit]( q"""       val p = ${c.prefix}       ..$valdefs       p.valuestack.push($f(..$args))       """)   } } 

this compiles (in scala 2.10.2 macro paradise plugin), didn't test whether works.