php - Passing a reference using call_user_func_array with variable arguments -

i have following code:

<?php class testme {     public static function foo(&$ref) {         $ref = 1;     } } call_user_func_array(array('testme', 'foo'), array(&$test)); var_dump($test); 

and correctly displays "1". want same, using "invoker" method, following:

<?php class testme {     public static function foo(&$ref) {         $ref = 1;     } }  class invoker {     public static function invoke($func_name) {         $args = func_get_args();         call_user_func_array(array('testme', $func_name), array_slice($args,1));     } }  $test = 2; invoker::invoke('foo', $test); var_dump($test); 

this throws strict standards error (php 5.5) , displays "2"

the question is, there way pass arguments reference testme::foo, when using func_get_args()? (workarounds welcome)

there no way reference out of func_get_args() because returns array copy of values passed in. see php reference.

additionally, since runtime pass reference no longer supported, must denote reference in each method/function signature. here example should work around overall issue of having invoker pass reference, there no work around func_get_args().

<?php  class testme {     public static function foo(&$ref) {         $ref  = 1;     } }  class invoker {     public static function invoke($func_name, &$args){            call_user_func_array(array('testme', $func_name), $args);     } }  $test  = 10;  $args[] = &$test;  invoker::invoke('foo', $args);  var_dump($test); 

if know want invoke reference, can work , perhaps have 2 invokers, 1 invoker::invokebyref normal invoker::invoke standard invoking copy.