linux - Printing all matches in a line using regular expression in awk -

say have line:

terminal="123" pwd="567"

i want select number portion using awk

awk 'match($1, /[0-9]+/){print substr($1, rstart, rlength)};match($2, /[0-9]+/){print    substr($2, rstart, rlength)}' file

this gives desired result.

123 567.

however there must other better way select both numbers without writing 2 match statements.

thanks.

here nice little solution awk:

awk '{gsub("[^0-9]+"," "); print}'

just converts consecutive non-digit characters 1 space, leaves 1 space before digit sequence 123.

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